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BharatShah5

I am a total new comer to powershell so please forgive me if my question sounds stupid. I found the script below from Yuri Posidelov which I tweaked to activate a process and show the window and send keystrokes to shut down the process which works great. However it fails if there are two process with the same name can anyone help me with this.


# Orignal code by Yuriy Posidelov





param([string] $proc="SBDDesktop", [string]$adm)

cls



Add-Type @"

using System;

using System.Runtime.InteropServices;

public class WinAp {

[DllImport("user32.dll")]

[return: MarshalAs(UnmanagedType.Bool)]

public static extern bool SetForegroundWindow(IntPtr hWnd);



[DllImport("user32.dll")]

[return: MarshalAs(UnmanagedType.Bool)]

public static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);

}



"@

$p = Get-Process |where {$_.mainWindowTItle }|where {$_.Name -like "$proc"}



if (($p -eq $null) -and ($adm -ne ""))

{

Start-Process "$proc" -Verb runAs

}

elseif (($p -eq $null) -and ($adm -eq ""))

{

Start-Process "$proc" #-Verb runAs

}

else

{

$h = $p.MainWindowHandle



[void] [WinAp]::SetForegroundWindow($h)

[void] [WinAp]::ShowWindow($h,3);



$wshell = New-Object -ComObject wscript.shell;

#$wshell.SendKeys('~')

$wshell.SendKeys('%fx')

sleep 1

$wshell.SendKeys('N')



}



#|format-table id,name,mainwindowtitle –AutoSize

# static extern IntPtr FindWindow(string lpClassName, string lpWindowName);

# powershell.exe -windowstyle hidden -file *.ps1 -adm "a"

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